Area under Curve

Area (in sq. units) lying in the first quadrant and bounded by the circle $x^{2}+y^{2}\text{=4 and the lines}x=0 and x=2$ is

The area between the parabola $y=x^{2}$ and the line $y=x$ is :

Compute the shaded area shown in the given figure.

The area bounded by the curves $y=|x|-1$ and $y=-|x|+1$ is

The area (in sq. units) of the region bounded by the curve $y=2 x-x^{2}$ and the X -axis is...

The area in square units of the region bounded by the curve $y=\sqrt{16-x^{2}}$ and lines $x=0, x=4$ above the X-axis is

Area (in sq.units) lying in the first quadrant and bounded by the circle $x^{2}+y^{2}=4$ and the lines $x=0$ and $x=2$ is

Find the area of the quadrilateral formed by the lines $y=2x+3,y=0,x=2 and x=4$ using integration.

The area of the region bounded by the curve $y=2x-x^{2}$ and $X$-axis is

The area of the region (in sq.units) bounded by the curve $y=2 \sqrt{1-x^{2}}$ and the X-axis is
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The area of the region bounded by curves $y=\sin x, y=\cos x$ and the lines $x=0, x=\dfrac{\pi}{4}$ is

The area (in square units) bounded by the line $y=x$, the X-axis and the lines $x=-2$ and $x=4$ is...

The area bounded by the curve $y=4 x-x^{2}$ and X - axis in square units, is

The area bounded by the curve $xy=c^{2},X\text{-axis and the ordinates}x=c,x=2c$ is

If the area of the region bounded by the curves $y=4-\dfrac{x^2}{4}$ and $y=\dfrac{x-4}{2}$ is equal to $\alpha$, then $6 \alpha$ equals